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25x^2-137=0
a = 25; b = 0; c = -137;
Δ = b2-4ac
Δ = 02-4·25·(-137)
Δ = 13700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13700}=\sqrt{100*137}=\sqrt{100}*\sqrt{137}=10\sqrt{137}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{137}}{2*25}=\frac{0-10\sqrt{137}}{50} =-\frac{10\sqrt{137}}{50} =-\frac{\sqrt{137}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{137}}{2*25}=\frac{0+10\sqrt{137}}{50} =\frac{10\sqrt{137}}{50} =\frac{\sqrt{137}}{5} $
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